C Exercises: Display the number of positive values, the minimum value, the maximum value and the average of all numbers

Last update on December 20 2024 13:14:40 (UTC/GMT +8 hours)

Count positive integers and display their min, max, and average

Write a C program that accepts integers from the user until a zero or a negative number, displays the number of positive values, the minimum value, the maximum value, and the average value.

Test data and expected output:
5 2 5 8 9 12 0

Pictorial Presentation:

Sample Solution:

C Code:

#include <stdio.h>
int main() {
    int a, ctr = 0, min_num, max_num, s = 0;
    double avg;

    // Prompt user for input
    printf("Input a positive integer:\n");

    // Read the first input value
    scanf("%d", &a);

    // Check if the input is positive
    if (a <= 0) {
        printf("No positive number entered\n");
        return 0;
    }

    // Initialize min_num and max_num with the first input value
    min_num = a;
    max_num = a;

    // Loop to process subsequent inputs
    while (a > 0) {
        s += a;
        ctr++;
        max_num = a > max_num ? a : max_num;
        min_num = a < min_num ? a : min_num;

        // Prompt for the next positive integer
        printf("Input next positive integer:\n");
        scanf("%d", &a);
    }

    avg = s / (double) ctr;

    // Display the results
    printf("Number of positive values entered is %d\n", ctr);
    printf("Maximum value entered is %d\n", max_num);
    printf("Minimum value entered is %d\n", min_num);
    printf("Average value is %0.4lf\n", avg);

    return 0;
}

Sample Output:

Input a positive integer:
Input next positive integer: 15
Input next positive integer: 25
Input next positive integer: 37
Input next positive integer: 43
Number of positive values entered is 4
Maximum value entered is 43
Minimum value entered is 15
Average value is 30.0000

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