Find integers divisible by 7 with a remainder of 2 or 3

Last update on May 20 2025 12:55:59 (UTC/GMT +8 hours)

Find integers divisible by 7 with a remainder of 2 or 3

Write a C program that finds all integer numbers that divide by 7 and have a remainder of 2 or 3 between two given integers.

Sample Solution:

C Code:

#include <stdio.h>
int main() {
    int x, y, temp, i, sum=0;

    // Prompt for user input
    printf("\nInput the first integer: ");
    scanf("%d", &x);
    printf("\nInput the second integer: ");
    scanf("%d", &y);

    // Swap values if x is greater than y
    if(x > y) {
        temp = y;
        y = x;
        x = temp;
    }

    // Iterate through numbers between x and y (exclusive)
    for(i = x+1; i < y; i++) {
        // Check if the number modulo 7 is 2 or 3
        if((i%7) == 2 || (i%7) == 3) {
            printf("%d\n", i);
        }
    }

    return 0;
}

Sample Output:

Input the first integer: 25                                            
                                                                       
Input the second integer: 45                                           
30                                                                     
31                                                                     
37                                                                     
38                                                                     
44

Flowchart:

For more Practice: Solve these Related Problems:

• Write a C program to find all integers within a range that are divisible by 5 and leave a remainder of 2.
• Write a C program to list integers between two numbers that satisfy multiple modulo conditions for a given divisor.
• Write a C program to find numbers in a specified range that leave a remainder of 2 or 3 when divided by 7.
• Write a C program to print integers that are divisible by 7 and have a remainder of either 1 or 4.

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