Divide two numbers or print if division isn't possible

Last update on March 18 2025 13:28:43 (UTC/GMT +8 hours)

C Practice Exercise

Write a program that reads two numbers and divides the first number by the second number. If division is not possible print "Division is not possible".

Sample Solution:

C Code:

#include <stdio.h>
int main() {
    int x, y;
    float div_result;

    // Prompt for user input
    printf("Input two numbers: ");
    printf("\nx: ");
    scanf("%d", &x);
    printf("y: ");
    scanf("%d", &y);

    // Check if division is possible
    if(y != 0) {
        div_result = x/y;
        printf("%.1f\n", div_result);
    } else {
        printf("Division not possible.\n");
    }

    return 0;
}

Sample Output:

Input two numbers:                                                     
x: 25                                                                  
y: 5                                                                   
5.0

Flowchart:

For more Practice: Solve these Related Problems:

Write a C program to divide two numbers and display both the quotient and the remainder, handling division by zero gracefully.
Write a C program to perform division and, if the divisor is zero, prompt the user to enter a new value.
Write a C program to compute the division of two integers and display the result as a floating-point number with error handling for zero divisor.
Write a C program to divide two numbers and, if division is not possible, print an appropriate error message and exit.

C programming Code Editor:

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