C Exercises: Check if a string is present in the last part of another string

Last update on September 19 2025 12:44:50 (UTC/GMT +8 hours)

Check if a string ends with another string

Write a C program that accepts two strings and checks whether the second string is present in the last part of the first string.

Sample Solution:

C Code:

#include <stdio.h>
#include <string.h>

int main() {
  short num1_len, num2_len;
  char num1[50], num2[50];

  // Prompt the user to input the first string
  printf("Input the first string:\n");
  scanf("%s", num1);

  // Prompt the user to input the second string
  printf("Input the second string:\n");
  scanf("%s", num2);

  // Get the lengths of the two strings
  num1_len = strlen(num1);
  num2_len = strlen(num2);

  // Check if the second string is present in the last part of the first string
  printf("Is second string present in the last part of the first string?\n");

  if (num1_len == num2_len) // If the lengths are equal
    if (strcmp(num1, num2) == 0) // If the strings are equal
      printf("Present!\n");
    else
      printf("Not Present!\n");
  else if (num1_len < num2_len) // If the first string is shorter than the second
    printf("Not Present!\n");
  else if (strstr(&num1[num1_len - num2_len - 1], num2)) // If the second string is found in the last part of the first string
    printf("Present!\n");
  else
    printf("Not Present!\n");

  return 0; // End of program
}

Sample Output:

Input the first string:
abcdef
Input the second string:
ef
Is second string present in the last part of the first string?
Present!

Flowchart:

For more Practice: Solve these Related Problems:

• Write a C program to check if one string is a suffix of another using pointer comparisons.
• Write a C program to determine whether the second string occurs at the end of the first string by comparing lengths and characters.
• Write a C program to implement a function that checks for a substring at the end of a string without using library functions.
• Write a C program to compare two strings and print "Present!" if the first string ends with the second using loops.

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