C Exercises: Array fill, replace each subsequent position of the array by one-third value of the previous
Replace array elements with one-third of the previous
Write a C program that reads an array (length 10), and replaces the first element of the array by a given number and replaces each subsequent position of the array by one-third the value of the previous.
Sample Solution:
C Code:
#include <stdio.h>
int main ()
{
int i;
double array_nums[10];
double n;
// Prompt user for input
printf("Input a number:\n");
scanf("%lf", &n);
// Initialize the first element of the array with the input value
array_nums[0] = n;
// Loop to generate and store subsequent array elements
for (i = 1; i < 10; i++)
{
n = n / 3; // Divide the current value by 3
array_nums[i] = n; // Store the result in the array
}
// Print the array elements
printf("\nArray elements:\n");
for (i = 0; i < 10; i++)
{
printf("array_nums[%d] = %.4lf\n", i, array_nums[i]);
}
return 0; // End of program
}
Sample Output:
Input a number: 35 Array elements: array_nums[0] = 35.0000 array_nums[1] = 11.6667 array_nums[2] = 3.8889 array_nums[3] = 1.2963 array_nums[4] = 0.4321 array_nums[5] = 0.1440 array_nums[6] = 0.0480 array_nums[7] = 0.0160 array_nums[8] = 0.0053 array_nums[9] = 0.0018
Flowchart:
For more Practice: Solve these Related Problems:
- Write a C program to modify an array so that each element (after the first) is one-third of its predecessor using loops.
- Write a C program to implement a function that updates an array with each element equal to one-third the previous element.
- Write a C program to use pointer arithmetic to replace each element in an array with one-third of the preceding element.
- Write a C program to recursively update an array where every element becomes one-third of the previous value.
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C programming Code Editor:
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