C Exercises: Fill the array elements with number o to n – 1 repeated times

Last update on December 20 2024 13:01:26 (UTC/GMT +8 hours)

Fill array with repeated values up to a given number

Write a C program that reads an array of integers (length 10), fills it with numbers from o to a (given number) n – 1 repeatedly, where 2 ≤ n ≤ 10.

Sample Solution:

C Code:

#include <stdio.h>
int main ()
{
  int n, i, array_nums[10], k;

  // Prompt user for input
  printf("Input an integer (2-10)\n");
  scanf("%d", &n);

  if (n >= 2 && n <= 10)
  {
    k = 0;

    // Loop to fill array with sequential numbers, starting from 0
    for (i = 0; i < 10; i++)
    {
      array_nums[i] = k;
      k++;

      if (k == n)
      {
        k = 0;
      }
    }

    // Loop to print array elements
    for (i = 0; i < 10; i++)
    {
      printf("array_nums[%d] = %d\n", i, array_nums[i]);
    }
  }
  return 0; // End of program
}

Sample Output:

Input an integer (2-10)
8
array_nums[0] = 0
array_nums[1] = 1
array_nums[2] = 2
array_nums[3] = 3
array_nums[4] = 4
array_nums[5] = 5
array_nums[6] = 6
array_nums[7] = 7
array_nums[8] = 0
array_nums[9] = 1

Flowchart:

C programming Code Editor:

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