C Exercises: Read an integer and compute all its divisors

Last update on December 20 2024 13:13:59 (UTC/GMT +8 hours)

Find and print all divisors of an integer

Write a C program that reads an integer and finds all the divisors of the said integer.

Sample Solution:

C Code:

#include <stdio.h>

int main () {
    int i, n;

    // Prompt user for input
    printf("Input a number (integer value):\n");

    // Read an integer value 'n' from user
    scanf("%d", &n);

    // Print a message indicating what the program will do
    printf("\nAll positive divisors of %d \n",n);

    // Loop through numbers from 1 to 'n'
    for (i = 1; i <= n; i++) {

        // Check if 'i' is a divisor of 'n'
        if (n % i == 0) {
            printf("%d\n", i); // Print 'i' if it is a divisor of 'n'
        }
    }

    return 0; // End of program
}

Sample Output:

Input a number (integer value):
35

All positive divisors of 35
1
5
7
35

Flowchart:

C programming Code Editor:

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