C Exercises: Read an integer and compute all its divisors

Last update on September 19 2025 12:45:13 (UTC/GMT +8 hours)

Find and print all divisors of an integer

Write a C program that reads an integer and finds all the divisors of the said integer.

Sample Solution:

C Code:

#include <stdio.h>

int main () {
    int i, n;

    // Prompt user for input
    printf("Input a number (integer value):\n");

    // Read an integer value 'n' from user
    scanf("%d", &n);

    // Print a message indicating what the program will do
    printf("\nAll positive divisors of %d \n",n);

    // Loop through numbers from 1 to 'n'
    for (i = 1; i <= n; i++) {

        // Check if 'i' is a divisor of 'n'
        if (n % i == 0) {
            printf("%d\n", i); // Print 'i' if it is a divisor of 'n'
        }
    }

    return 0; // End of program
}

Sample Output:

Input a number (integer value):
35

All positive divisors of 35
1
5
7
35

Flowchart:

For more Practice: Solve these Related Problems:

• Write a C program to find all positive divisors of an integer using a loop with conditional modulus checks.
• Write a C program to store all divisors of a number in an array and then print them in sorted order.
• Write a C program to recursively determine and print all divisors of a given integer.
• Write a C program to optimize divisor search by iterating only up to the square root of the number and printing corresponding pairs.

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