C Exercises: Sum of all odd, even values between two integers

C Basic Declarations and Expressions: Exercise-108 with Solution

Write a C program that reads two integer values and calculates the sum of all odd numbers between them.

Sample Solution:

C Code:

#include <stdio.h>
int main () {
    // Declare variables for input, counters, and sum of odd and even numbers
    int a, b, i, ctr = 0, sum_odd = 0, sum_even = 0;

    // Prompt the user to input the first integer number
    printf("Input the first integer number:\n");
    scanf("%d", &a);

    // Prompt the user to input the second integer number (greater than the first integer)
    printf("Input the second integer number (greater than first integer):\n");
    scanf("%d", &b);

    // Check if b is greater than a
    if (b > a)
    {
        // Calculate the sum of all odd values between a and b
        for (i = a; i <= b; i++){

            if (i % 2 != 0){      
                sum_odd = sum_odd + i;
            }
        }

        // Print the sum of all odd values
        printf("Sum of all odd values between %d and %d:", a, b);
        printf("\n%d", sum_odd);

        // Reset counter
        ctr = 0;
   
        // Calculate the sum of all even values between a and b
        for (i = a; i <= b; i++){
            if (i % 2 == 0){
                sum_even = sum_even + i;
            }
        }

        // Print the sum of all even values
        printf("\nSum of all even values between %d and %d:", a, b);
        printf("\n%d", sum_even);
    }
}

Sample Output:

Input the first integer number:
25
Input the second integer number (greater than first integer):
45
Sum of all odd values between 25 and 45:
385
Sum of all even values between 25 and 45:
350

Flowchart:

C programming Code Editor:

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