C Exercises: Shift an element in left direction and return a new array

Last update on December 20 2024 13:00:49 (UTC/GMT +8 hours)

Write a C program to shift an element in the left direction and return a newly created array.

C Code:

#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'print_array'
void print_array(int parray[], int size);

int main(void){ 
    int arr_size;

    // Declaration and initialization of an integer array 'a1'
    int a1[] = {10, 20, 30, 40};
    arr_size = sizeof(a1)/sizeof(a1[0]);

    // Printing the elements of the original array 'a1'
    printf("Elements in original array are: ");  
    print_array(a1, arr_size);

    // Declaration and initialization of an integer array 'result'
    int result[arr_size];

    // Loop to generate the elements of the new array 'result'
    for (int i = 0; i < arr_size; i++)
    {
        result[i] = a1[(i + 1) % arr_size];
    }

    // Printing the elements of the new array 'result'
    printf("\nElements in new array are: ");  
    print_array(result, arr_size);
}         

// Definition of the 'print_array' function
void print_array(int parray[], int size)
{
    int i;      
    // Loop to print the elements of the array
    for( i = 0; i < size - 1; i++)  
    {  
        printf("%d, ", parray[i]);  
    } 
    // Printing the last element
    printf("%d ", parray[i]);  
    printf("\n");   
}

Sample Output:

Elements in original array are: 10, 20, 30, 40 

Elements in new array are: 20, 30, 40, 10

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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