C Exercises: Check a given array of integers and return true if there is a 3 with a 5 somewhere later in the given array

Last update on December 20 2024 13:13:23 (UTC/GMT +8 hours)

Write a C program to check a given array of integers and return true if there is a 3 with a 5 somewhere later in the given array.

C Code:

#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'test'
int test(int numbers[], int arr_size);

int main(void){
    int arr_size;

    // Declaration and initialization of an integer array 'array1'
    int array1[] = {1, 2, 3, 4};
    arr_size = sizeof(array1)/sizeof(array1[0]);

    // Printing the result of the 'test' function for 'array1'
    printf("%d",test(array1, arr_size));

    // Declaration and initialization of an integer array 'array2'
    int array2[] = {3, 3, 5, 5, 5, 5};
    arr_size = sizeof(array2)/sizeof(array2[0]);

    // Printing the result of the 'test' function for 'array2'
    printf("\n%d",test(array2, arr_size));

    // Declaration and initialization of an integer array 'array3'
    int array3[] = {2, 5, 5, 7, 8, 10};
    arr_size = sizeof(array3)/sizeof(array3[0]);

    // Printing the result of the 'test' function for 'array3'
    printf("\n%d",test(array3, arr_size));
}

// Definition of the 'test' function
int test(int numbers[], int arr_size)
{
    int three = 0;

    // Looping through the elements of the array
    for (int i = 0; i < arr_size; i++)
    {
        // Checking if 'three' is true and the current element is 5, then return 1
        if (three && numbers[i] == 5)
            return 1;

        // Checking if the current element is 3, then set 'three' to true
        if (numbers[i] == 3)
            three = 1;
    }

    // If no consecutive occurrence of 3 followed by 5 were found
    return 0;
}

Sample Output:

0
1
0

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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