C Exercises: Check if an array of integers contains a 3 next to a 3 or a 5 next to a 5 or both

C-programming basic algorithm: Exercise-60 with Solution

Write a C program to check if an array of integers contains a 3 next to a 3 or a 5 next to a 5 or both.

C Code:

#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'test'
int test(int numbers[], int arr_size);

int main(void){
    int arr_size;

    // Declaration and initialization of an integer array 'array1'
    int array1[] = {1, 5, 5, 5, 5};
    arr_size = sizeof(array1)/sizeof(array1[0]);

    // Printing the result of the 'test' function for 'array1'
    printf("%d",test(array1, arr_size));

    // Declaration and initialization of an integer array 'array2'
    int array2[] = {2, 7, 8, 10};
    arr_size = sizeof(array2)/sizeof(array2[0]);

    // Printing the result of the 'test' function for 'array2'
    printf("\n%d",test(array2, arr_size));

    // Declaration and initialization of an integer array 'array3'
    int array3[] = {3, 3, 3, 5, 5, 5};
    arr_size = sizeof(array3)/sizeof(array3[0]);

    // Printing the result of the 'test' function for 'array3'
    printf("\n%d",test(array3, arr_size));
}

// Definition of the 'test' function
int test(int numbers[], int arr_size)
{
    int t_num = 0, f_num = 0;

    // Looping through the elements of the array
    for (int i = 0; i < arr_size - 1; i++)
    {
        // Checking if the current element and the next element are both 3
        if (numbers[i] == 3 && numbers[i + 1] == 3)
            t_num = 1;
        else
            t_num = 0;

        // Checking if the current element and the next element are both 5
        if (numbers[i] == 5 && numbers[i + 1] == 5)
            f_num = 1;
        else
            f_num = 0;
    }

    // Using XOR (^) to check if only one of them is true
    return t_num ^ f_num;
}

Sample Output:

1
0
1

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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