C Exercises: Check if a given array of integers contains no 3 or a 5

#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'test'
int test(int nums[], int arr_size);

int main(void){
    int arr_size;

    // Declaration and initialization of an integer array 'array1'
    int array1[] = {1, 5, 5, 5, 5};
    arr_size = sizeof(array1)/sizeof(array1[0]);

    // Printing the result of the 'test' function for 'array1'
    printf("%d",test(array1, arr_size));

    // Declaration and initialization of an integer array 'array2'
    int array2[] = {3, 3, 3, 3 };
    arr_size = sizeof(array2)/sizeof(array2[0]);

    // Printing the result of the 'test' function for 'array2'
    printf("\n%d",test(array2, arr_size));

    // Declaration and initialization of an integer array 'array3'
    int array3[] = {3, 3, 3, 5, 5, 5};
    arr_size = sizeof(array3)/sizeof(array3[0]);

    // Printing the result of the 'test' function for 'array3'
    printf("\n%d",test(array3, arr_size));

    // Declaration and initialization of an integer array 'array4'
    int array4[] = {1, 6, 8, 10};
    arr_size = sizeof(array4)/sizeof(array4[0]);

    // Printing the result of the 'test' function for 'array4'
    printf("\n%d",test(array4, arr_size));
}

// Definition of the 'test' function
int test(int nums[], int arr_size)
{
    int three = 0, five = 0;

    // Looping through the elements of the array
    for (int i = 0; i < arr_size; i++)
    {
        // Checking if the current element is 3
        if (nums[i] == 3)
        {
            three++;
        }

        // Checking if the current element is 5
        if (nums[i] == 5)
        {
            five++;
        }

        // If both 3 and 5 are found, return 0 (false)
        if (three && five)
        {
            return 0;
        }
    }

    return 1; // If no instance of both 3 and 5, return 1 (true)
}